This C Program Converts the given Hexadecimal to Binary. Binary number is a number that can be represented using only two numeric symbols – 0 and 1. A number in base 2. Hexadecimal is base 16 arithmetic where each digit is a value from 0 to 15, rather than the 0-9 of base 10.
Here is source code of the C program to Convert Hexadecimal to Binary. The C program is successfully compiled and run on a Linux system. The program output is also shown
below.

/*
* C Program to Convert Hexadecimal to Binary
*/
#include <stdio.h>
#define MAX 1000

int main()
{
char binarynum[MAX], hexa[MAX];
long int i = 0;

printf("Enter the value for hexadecimal ");
scanf("%s", hexa);
printf("\n Equivalent binary value: ");
while (hexa[i])
{
switch (hexa[i])
{
case '0':
printf("0000"); break;
case '1':
printf("0001"); break;
case '2':
printf("0010"); break;
case '3':
printf("0011"); break;
case '4':
printf("0100"); break;
case '5':
printf("0101"); break;
case '6':
printf("0110"); break;
case '7':
printf("0111"); break;
case '8':
printf("1000"); break;
case '9':
printf("1001"); break;
case 'A':
printf("1010"); break;
case 'B':
printf("1011"); break;
case 'C':
printf("1100"); break;
case 'D':
printf("1101"); break;
case 'E':
printf("1110"); break;
case 'F':
printf("1111"); break;
case 'a':
printf("1010"); break;
case 'b':
printf("1011"); break;
case 'c':
printf("1100"); break;
case 'd':
printf("1101"); break;
case 'e':
printf("1110"); break;
case 'f':
printf("1111"); break;
default:
printf("\n Invalid hexa digit %c ", hexa[i]);
return 0;
}
i++;
}
return 0;
}

Output:
$ cc pgm4.c
$ a.out
Enter the value for hexadecimal ab
Equivalent binary value: 10101011