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C# Program to Find Volume and Surface Area of Cone

C# Program to Find Volume and Surface Area of Cone

This is a C# Program to calculate area and volume of a cone.

Problem Description

This C# Program Calculates Area and Volume of a Cone.

Problem Solution

Here radius and height of the cone is obtained from the user and the surface area and its volume its calculated.

Program/Source Code

Here is source code of the C# Program to Calculate Area and Volume of a Cone. The C# program is successfully compiled and executed with Microsoft Visual Studio. The program output is also shown below.

/*
 * C# Program to Calculate Area and Volume of a Cone
 */
using System;
using System.IO;
class program
{
    public static void Main()
    {
        double r, h, surface_area, volume;
        double PI = 3.14;
        Console.WriteLine("Enter the Radius and Height of a cone : ");
        r = Convert.ToDouble(Console.ReadLine());
        h = Convert.ToDouble(Console.ReadLine());
        surface_area = PI * r * (r + Math.Sqrt(r * r + h * h));
        volume = (1.0 / 3) * PI * r * r * h;
        Console.WriteLine("Surface Area of cone is : {0} ", surface_area);
        Console.WriteLine("Volume of Cone is : {0}", volume);
        Console.Read();
    }
}
Program Explanation

In this C# program, library function defined in <math.h> header file is used. We are reading the radius and height of a cone using ‘r’ and ‘h’ variable respectively. To compute the area and volume of a triangle the formula are used

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Surface_area = 2 * Pi * r * (r + h),

Volume = Pi * r * r * h

Where Pi = 22/7.

 
Runtime Test Cases
 
Enter the Radius and Height of a cone : 3 3
Surface Area of cone is : 68.2256752726637
Volume of Cone is : 28.26

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