Output enter values of adjacency matrix for a 7 node graph: enter values for 1 row 0 3 6 0 0 0 0 enter values for 2 row 3 0 2 4 0 0 0 enter values for 3 row 6 2 0 1 4 2 0 enter values for 4 row 0 4 1 0 2 0 4 enter values for 5 row 0 0 4 2 0 2 1 enter values for 6 row 00 0 2 0 2 0 1 enter values for 7 row 0 0 0 4 1 1 0 MINIMUM SPANNING TREE AND ORDER OF TRAVERSAL: source node:0 destination node:1 weight of node3 source node:1 destination node:2 weight of node2 source node:2 destination node:3 weight of node1 source node:2 destination node:5 weight of node2 source node:5 destination node:6 weight of node1 source node:6 destination node:4 weight of node1
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C++ Program to Find Minimum Spanning Tree using Prim?s Algorithm
C++ Program to Find Minimum Spanning Tree using Prim’s Algorithm
This C++ program depicts the Prim’s Algorithm which finds the minimal spanning tree(tree consisting of the minimum weights of edges connecting any two vertices) in a graph.
Here is the source code of the C++ program to display the destination node, start node and the weight of node connecting the two using Prim’s Algorithm such that the resultant values of weights of edges are the smallest possible. This C++ program is successfully compiled and run on DevCpp, a C++ compiler. The program output is given below.
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/*
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* C++ Program to find MST(Minimum Spanning Tree) using
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* Prim's Algorithm
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*/
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#include <iostream>
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#include <conio.h>
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using namespace std;
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struct node
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{
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int fr, to, cost;
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}p[6];
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int c = 0, temp1 = 0, temp = 0;
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void prims(int *a, int b[][7], int i, int j)
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{
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a[i] = 1;
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while (c < 6)
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{
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int min = 999;
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for (int i = 0; i < 7; i++)
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{
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if (a[i] == 1)
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{
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for (int j = 0; j < 7; )
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{
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if (b[i][j] >= min || b[i][j] == 0)
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{
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j++;
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}
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else if (b[i][j] < min)
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{
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min = b[i][j];
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temp = i;
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temp1 = j;
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}
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}
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}
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}
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a[temp1] = 1;
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p[c].fr = temp;
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p[c].to = temp1;
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p[c].cost = min;
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c++;
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b[temp][temp1] = b[temp1][temp]=1000;
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}
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for (int k = 0; k < 6; k++)
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{
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cout<<"source node:"<<p[k].fr<<endl;
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cout<<"destination node:"<<p[k].to<<endl;
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cout<<"weight of node"<<p[k].cost<<endl;
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}
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}
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int main()
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{
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int a[7];
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for (int i = 0; i < 7; i++)
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{
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a[i] = 0;
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}
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int b[7][7];
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for (int i = 0; i < 7; i++)
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{
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cout<<"enter values for "<<(i+1)<<" row"<<endl;
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for (int j = 0; j < 7; j++)
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{
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cin>>b[i][j];
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}
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}
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prims(a, b, 0, 0);
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getch();
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}
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