This C program, using iteration, searches for an element in a linked list. A linked list is an ordered set of data elements, each containing a link to its successor.
Here is the source code of the C program to search for an element in a linked list. The C program is successfully compiled and run on a Linux system. The program output is also shown below.
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/* -
* C Program to Search for an Element in the Linked List without -
* using Recursion -
*/ -
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#include <stdio.h> -
#include <stdlib.h> -
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struct node -
{ -
int a;
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struct node *next;
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};
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void generate(struct node **, int);
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void search(struct node *, int);
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void delete(struct node **);
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int main()
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{ -
struct node *head = NULL;
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int key, num;
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printf("Enter the number of nodes: ");
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scanf("%d", &num);
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printf("\nDisplaying the list\n");
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generate(&head, num);
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printf("\nEnter key to search: ");
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scanf("%d", &key);
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search(head, key);
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delete(&head);
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return 0;
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} -
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void generate(struct node **head, int num)
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{ -
int i;
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struct node *temp;
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for (i = 0; i < num; i++)
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{ -
temp = (struct node *)malloc(sizeof(struct node));
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temp->a = rand() % num;
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if (*head == NULL)
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{ -
*head = temp;
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temp->next = NULL;
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} -
else -
{ -
temp->next = *head;
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*head = temp;
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} -
printf("%d ", temp->a);
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} -
} -
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void search(struct node *head, int key)
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{ -
while (head != NULL)
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{ -
if (head->a == key)
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{ -
printf("key found\n");
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return;
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} -
head = head->next;
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} -
printf("Key not found\n");
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} -
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void delete(struct node **head)
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{ -
struct node *temp;
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while (*head != NULL)
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{ -
temp = *head;
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*head = (*head)->next;
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free(temp);
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} -
}
$ gcc search_iter.c -o search_iter $ a.out Enter the number of nodes: 10 Displaying the list 3 6 7 5 3 5 6 2 9 1 Enter key to search: 2 key found
