Here is source code of the C program to create a linked list & display the elements in the list. The C program is successfully compiled and run on a Linux system. The program output is also shown below.
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/* -
* C program to create a linked list and display the elements in the list -
*/ -
#include <stdio.h> -
#include <malloc.h> -
#include <stdlib.h> -
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void main()
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{ -
struct node -
{ -
int num;
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struct node *ptr;
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};
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typedef struct node NODE;
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NODE *head, *first, *temp = 0;
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int count = 0;
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int choice = 1;
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first = 0;
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while (choice)
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{ -
head = (NODE *)malloc(sizeof(NODE));
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printf("Enter the data item\n");
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scanf("%d", &head-> num);
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if (first != 0)
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{ -
temp->ptr = head;
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temp = head;
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} -
else -
{ -
first = temp = head;
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} -
fflush(stdin);
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printf("Do you want to continue(Type 0 or 1)?\n");
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scanf("%d", &choice);
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} -
temp->ptr = 0;
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/* reset temp to the beginning */ -
temp = first;
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printf("\n status of the linked list is\n");
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while (temp != 0)
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{ -
printf("%d=>", temp->num);
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count++; -
temp = temp -> ptr;
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} -
printf("NULL\n");
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printf("No. of nodes in the list = %d\n", count);
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}
$ cc pgm98.c $ a.out Enter the data item 5 Do you want to continue(Type 0 or 1)? 0 status of the linked list is 5=>NULL No. of nodes in the list = 1 $ a.out Enter the data item 5 Do you want to continue(Type 0 or 1)? 1 Enter the data item 9 Do you want to continue(Type 0 or 1)? 1 Enter the data item 3 Do you want to continue(Type 0 or 1)? 0 status of the linked list is 5=>9=>3=>NULL No. of nodes in the list = 3
Here is a source code of the C Program to read a linked list in reverse. The C program is successfully compiled and run on a Linux system. The program output is also shown below.
/*
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* C Program to Read a Linked List in Reverse
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*/
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#include <stdio.h>
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#include <stdlib.h>
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struct node
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{
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int num;
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struct node *next;
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};
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void create(struct node **);
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void reversedisplay(struct node *);
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void release(struct node **);
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void display(struct node *);
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int main()
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{
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struct node *p = NULL;
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struct node_occur *head = NULL;
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int n;
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printf("Enter data into the list\n");
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create(&p);
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printf("Displaying the nodes in the list:\n");
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display(p);
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printf("Displaying the list in reverse:\n");
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reversedisplay(p);
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release(&p);
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return 0;
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}
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void reversedisplay(struct node *head)
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{
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if (head != NULL)
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{
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reversedisplay(head->next);
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printf("%d\t", head->num);
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}
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}
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void create(struct node **head)
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{
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int c, ch;
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struct node *temp, *rear;
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do
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{
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printf("Enter number: ");
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scanf("%d", &c);
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temp = (struct node *)malloc(sizeof(struct node));
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temp->num = c;
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temp->next = NULL;
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if (*head == NULL)
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{
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*head = temp;
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}
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else
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{
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rear->next = temp;
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}
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rear = temp;
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printf("Do you wish to continue [1/0]: ");
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scanf("%d", &ch);
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} while (ch != 0);
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printf("\n");
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}
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void display(struct node *p)
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{
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while (p != NULL)
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{
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printf("%d\t", p->num);
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p = p->next;
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}
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printf("\n");
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}
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void release(struct node **head)
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{
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struct node *temp = *head;
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*head = (*head)->next;
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while ((*head) != NULL)
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{
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free(temp);
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temp = *head;
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(*head) = (*head)->next;
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}
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}
$ cc readreverse.c
$ ./a.out
Enter data into the list
Enter number: 1
Do you wish to continue [1/0]: 1
Enter number: 2
Do you wish to continue [1/0]: 1
Enter number: 3
Do you wish to continue [1/0]: 1
Enter number: 4
Do you wish to continue [1/0]: 1
Enter number: 5
Do you wish to continue [1/0]: 0
Displaying the nodes in the list:
1 2 3 4 5
Displaying the list in reverse:
5 4 3 2 1
