To express x% as a fraction : We have , x% = x/100.
Thus, 20% =20/100 =1/5; 48% =48/100 =12/25, etc.
To express a/b as a percent : We have, a/b =((a/b)*100)%.
Thus, ¼ =[(1/4)*100] = 25%; 0.6 =6/10 =3/5 =[(3/5)*100]% =60%.
[R/(100+R))*100]%.
If the price of the commodity decreases by R%,then the increase in consumption so as to decrease the expenditure is
[(R/(100-R)*100]%.
3. Results on Population : Let the population of the town be P now and suppose it increases at the rate of
R% per annum, then :
4. Results on Depreciation : Let the present value of a machine be P. Suppose it depreciates at the rate
R% per annum. Then,
[(R/(100+R))*100]%.
If A is R% less than B , then B is more than A by
[(R/(100-R))*100]%.